Rozwiaz równanie 3x'3-x'2+9x-3=0
3x'3 - x'2 + 9x - 3 = 0
x²(3x - 1) + 3(3x - 1) = 0
(x² + 3)(3x - 1) = 0
x² + 3 = 0 lub 3x - 1 = 0
Δ = 0 - 12 = -12 < 0 3x = 1
nie ma pierwiastków x = 1/3
odp. x = 1/3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
3x'3 - x'2 + 9x - 3 = 0
x²(3x - 1) + 3(3x - 1) = 0
(x² + 3)(3x - 1) = 0
x² + 3 = 0 lub 3x - 1 = 0
Δ = 0 - 12 = -12 < 0 3x = 1
nie ma pierwiastków x = 1/3
odp. x = 1/3