rozwiaz nierownosc x kwadrat - x - 6 <0
rozwiaz rownanie x do potegi 3 -11 x kwadrat -3x +33= 0
x² - x - 6 < 0
Δ = 1 + 24 = 25
√Δ = 5
x₁ = 1 - 5 / 2 = -2
x₂ = 1 + 5 / 2 = 3
Rysujemy wykres z ramionami do góry i wyszukujemy wartości ujemnnw
x ∈ ( -2 , 3 )
=====================================
x³ - 11x² - 3x + 33 = 0
x²(x - 11) - 3 (x -11) = 0
(x² -3) (x-11) = 0
x² - 3 = 0 lub x - 11 = 0
x =- √3 lub x=√3 lub x = 11
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x² - x - 6 < 0
Δ = 1 + 24 = 25
√Δ = 5
x₁ = 1 - 5 / 2 = -2
x₂ = 1 + 5 / 2 = 3
Rysujemy wykres z ramionami do góry i wyszukujemy wartości ujemnnw
x ∈ ( -2 , 3 )
=====================================
x³ - 11x² - 3x + 33 = 0
x²(x - 11) - 3 (x -11) = 0
(x² -3) (x-11) = 0
x² - 3 = 0 lub x - 11 = 0
x =- √3 lub x=√3 lub x = 11