Rozwiąż;
4x+5-x=-7
2{8-x}-3{9-x}=0
{4x-5}-2{x+3}=-4
wyrażenia algebraiczne, x=?
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1)4x+5-x=-7
3x=-5-7
3x=-12/:3
x=-4
2)2{8-x}-3{9-x}=0
16-2x-27+3x=0
x=-16+27
x=11
3){4x-5}-2{x+3}=-4
4x-5-2x-6=-4
2x=5+6-4
2x=7/:2
x=7/2=3 1/2
4x+5-x=-7
4x -x = - 7 - 5
3x = - 12
x= - 12 : 3
x= - 4
spr.
4x+5-x=-7
4*(-4) + 5 -(-4) = - 7
-16 + 5 + 4 = - 7
-16 + 9 = - 7
- 7 = - 7
L=P
2(8-x)-3(9-x)=0
16 - 2x - 27 + 3x= 0
-2x + 3x +16 - 27 = 0
x - 11= 0
x= 11
spr.
2(8-x)-3(9-x)=0
2(8 - 11) - 3(9 - 11) = 0
2*(-3) - 3(-2) = 0
- 6 -(-6) = 0
- 6 + 6 = 0
0=0
L=P
(4x-5)-2(x+3)=-4
4x - 5 - 2x - 6 = - 4
4x -2x - 5 - 6 = - 4
2x -11 = -4
2x= -4 + 11
2x= 7
x= 7 : 2
x= 3,5
spr.
(4x-5)-2(x+3)=-4
(4*3,5 - 5) -2(3,5+3) = -4
(14 - 5) -2(6,5) = - 4
9 - 13 = - 4
-4 = -4
L=P