rozwiąż zadania
a) 2a(b-3)-2b(a-3)=
b) 5a(a-2)+2a(a+5)=
c) a(b+a-ab)=
d) -2(x+4-y+z)=
e) 5(a+b)-(b-a)
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z
klaa 1 gim
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a)2ab-6a-2ab+6b=0
b)5a'-10+2a'+10=7a'
c)ab+a'-a'b
d)-2x-8+2y-2z
e)5a+5b-b+a 6a+4b
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z z
' to jest do potęgi drugiej