Rozwiąż wyrażenia algebraiczne : 3o²-(b²-4o)-(3o²-3)+b²-3= 3(g+1)-(-5g)-4g-3= 8(b+3i²)+3(2i-8i²)-3b= 8(i+3e²)+3(2e-8e²)-3i= Proszę o obliczenia.
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3o²-(b²-4o)-(3o²-3)+b²-3=
=3o²-b²+4o-3o²+3+b²-3=
=4o
3(g+1)-(-5g)-4g-3=
=3g+3+5g-4g-3=
= 4g
8(b+3i²)+3(2i-8i²)-3b=
=8b+24i²+6i-24i²-3b=
= 5b+6i
8(i+3e²)+3(2e-8e²)-3i=
=8i+24e²+6e-24e²-3i=
= 5i+6e
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