Question

Rozwiąż układy równan (x+3)do potegi2-(y-1)do potegi2=(x-y)(x+y) 3x-7y=0

Answer 1

(x+3)2-(y-1)2=(x-y)(x+y)

3x-7y=0

 

x2+6x+9-y2+2y-1=x2-y2

3x-7y=0

 

x2-x2-y2+y2+6x+2y=-8

3x-7y=0

 

6x+2y=-8

3x-7y=0 / * (-2)

 

6x+2y=-8

-6x+14y=0

.................

16y=-8

y=- 1/2

 

6x+2 * (-1/2) = -8

6x= -8+1

x=- 7/6=- 1 1/6

 

x= - 1  1/6

y= - 1/2