September 2018 2 17 Report

Rozwiąż układy równań

\left \{ {{3(x-\frac{1}{2})+2(y+3)=3\frac{1}{2}} \atop {\frac{3x-1}{3} -\frac{y+3}{2}=-1}} \right

\left \{ {{\frac{x-3}{4}-\frac{y+5}{2}=-1,5 } \atop {\frac{x-3}{2}-\frac{2y-7}{3}=1 }} \right

\left \{ {{\frac{2x-5}{2}-\frac{x-6y}{4}=\frac{x+y}{2}} \atop {\frac{3x-1}{10}+\frac{2y-5}{5}=\frac{2x+y}{2}}} \right

\left \{ {{\frac{x-3}{5}-\frac{y+1}{2}=1-(x-y)} \atop {\frac{4x-1}{3}-\frac{y-3}{6}=-2(x-y)}} \right

+3 zadania w zalączniku


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.