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3x-5y=3
5x=10/-5
x=5
b)∫x+y=2
x-y=0
2x=2/-2
x=0
c)∫x+2y=9
-x-3y=16
-y=25/-
y=-25
d)∫3x+2y=13
2x+y=11/*-2
3x+2y=13
-4x-2y=-22
-x=-9/-
x=9
e)∫5x+3y=0
-x-2y=7/*5
5x+3y=0
-5x-10y=35
-7y=35/-7
y=-5
chyba tak ma byc pozdrawiam XD