Rozwiąż układy równań metodą podstawiania:
(Dwa nawiasy traktujcie jak jeden duzy)
(4a-2=b
(3a+7b=1,5
(5x+4-2y
(4x+y=3
(6x-3y=9
(x+5y=-9,5
(3m+n=9
(2m-5n=-11
(2x-y=10
(x+5y=-17
Proszę o bardzo szybką odp. Z góry dzięki.
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(4a-2=b
(3a+7b=1,5
4a-2=b
3a+7(4a-2)=1,5
4a-2=b
3a+28a-14=1,5
4a-2=b
31a=15,5/:31
4a-2=b
a=0,5
4*0,5-2=b
a=0,5
b=0
(5x+4-2y
(4x+y=3
5x+4-2y
y=3-4x
5x+4-2(3-4x)
y=3-4x
5x+4-6+8x
y=3-4x
13x=2/:13
y=3-4x
x≈0,15
y=3-4x
y=3-4*0,15
y=3-0,6
y=2,4
(6x-3y=9
(x+5y=-9,5
6x-3y=9
x=-9,5-5y
6(-9,5-5y)-3y=9
x=-9,5-5y
-57-30y-3y=9
x=-9,5-5y
-33y=66/:(-33)
y=-2
x=-9,5-5y
x=-9,5-5*(-2)
x=-9,5+10
x=0,5
(3m+n=9
(2m-5n=-11
n=9-3m
2m-5(9-3m)=-11
n=9-3m
2m-45+15m=-11
n=9-3m
17m=34/:17
m=2
n=9-3m
n=9-3*2
n=9-6
n=3
(2x-y=10
(x+5y=-17
(2x-y=10
x=-17-5y
2(-17-5y)-y=10
x=-17-5y
-34-10y-y=10
x=-17-5y
-11y=44/:(-11)
y=-4
x=-17-5y
x=-17-5*(-4)
x=-17+20
x=3
liczę na naj ;d