September 2018 0 10 Report

Rozwiąż układy równań metodą podstawiania: {x - 2y = 3 {4x - 3y = 2

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mmartynkaa
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mmartynkaa

x-2y=3

4x-3y=2

 

x=3+2y

4(3+2y)-3y=2

 

12+8y-3y=2

x=3+2y

 

10=-5y

x=3+2y

 

y=-2

x=3+2y

 

x=3-4

y=-2

 

x=-1

y=-2

 

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\left \{ {{x-2y=3} \atop {4x-3y=2}} \right \left \{ {{x=3+2y} \atop {4(3+2y)-3y=2}} \right \left \{ {{x=3+2y} \atop {12+8y-3y=2}} \right \left \{ {{x=3+2y} \atop {5y=2-12}} \right \left \{ {{x=3+2y} \atop {y=-2}} \right \left \{ {{x=3+2\times(-2)} \atop {y=-2}} \right \left \{ {{x=-1} \atop {y=-2}} \right


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