rozwiąż układ równań
y=x²-2x-8
y=-3x-2
-3x-2 = x²-2x-8
x²-2x-8 + 3x+2 = 0
x²+ x -6 = 0
Δ = b² -4ac = 1² -4 *1*(-6) = 1 + 24 = 25
√Δ = √25 = 5
x₁ =( -b-√Δ)/2a = (-1-5)/2 = -6/2 = -3
x₂ = (-b+√Δ)/2a= (-1+5)/2 = 4/2 = 2
gdy :
x = -3
y = -3x -2
y = -3*(-3) -2 = 9-2 =7
gdy:
x = 2
y = -3*2 -2 = -6-2 =-8
y= -3x-2
-3x-2=x2 - 2x - 8
-3x-2 -x2 + 2x + 8 =0
-x2 -x +6 =0 /(*-1)
x2+x-6=0
z tego liczysz delte i pierwiastki. Dasz rade?
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
y=x²-2x-8
y=-3x-2
y=-3x-2
-3x-2 = x²-2x-8
y=-3x-2
x²-2x-8 + 3x+2 = 0
y=-3x-2
x²+ x -6 = 0
Δ = b² -4ac = 1² -4 *1*(-6) = 1 + 24 = 25
√Δ = √25 = 5
x₁ =( -b-√Δ)/2a = (-1-5)/2 = -6/2 = -3
x₂ = (-b+√Δ)/2a= (-1+5)/2 = 4/2 = 2
gdy :
x = -3
y = -3x -2
x = -3
y = -3*(-3) -2 = 9-2 =7
gdy:
x = 2
y = -3x -2
x = -3
y = -3*2 -2 = -6-2 =-8
y= -3x-2
-3x-2=x2 - 2x - 8
-3x-2 -x2 + 2x + 8 =0
-x2 -x +6 =0 /(*-1)
x2+x-6=0
z tego liczysz delte i pierwiastki. Dasz rade?