Rozwiąż układ równan:
2y+3z=102
z=y-6
2z=3x
2y+3y-18=102
5y=120
y=24
z=24-6
z=18
36=3x
x=12
podstawiamy z pod układ:
2y + 3(y-6) = 102
z= y-6
2(y-6)=3x
2y + 3y - 18 = 102
2y - 12 = 3x
5y= 120 / 5
2y-12= 3x
z= 18
48-12=3x / : 3
x= 12
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2y+3z=102
z=y-6
z=y-6
2y+3y-18=102
5y=120
y=24
z=y-6
z=24-6
z=18
2z=3x
36=3x
x=12
podstawiamy z pod układ:
2y + 3(y-6) = 102
z= y-6
2(y-6)=3x
2y + 3y - 18 = 102
z= y-6
2y - 12 = 3x
5y= 120 / 5
z= y-6
2y-12= 3x
y=24
z= 18
48-12=3x / : 3
y=24
z=18
x= 12