September 2018 1 12 Report

Rozwiąż układ równań

\left \{ {{6(x+y)=10y} \atop {y-x=0.5}} \right

\left \{ {{10(y+2)+3(x-5)=x-5} \atop {25(y+2)+3(x-5)=-10}} \right

\left \{ {{y/2 + x/4 - 1/5 (x+2)=1,1} \atop {x-2y+4=x/2 +3/4(y-0,5)}


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