Question

Rozwiąż układ równań:

(x+2)²-(y+2)²=3+(x-3)²-y²
x-5y+3*2x+3 nad 2 -1½+3y nad 3=0

Answer 1

1. (x+2)²-(y+2)²=3+(x-3)²-y²
(x²+2²)-(y²+2²)=3+(x²-9)-y²
x²+-y²+4=3+x²-9-y²
x²+4-y²+4-x²=3-9-y²
x²+4-y²+4-x²=-6-y²
4-y²+y²=-6-4
-6-4-4=-14