rozwiąż układ równań metodą przeciwnych współczynników
a)x-y=1
2x+3y=7
b)-x+2y=1
2x-3y=6
a)x-y=12x+3y=7
-2x+2y = -2
2y+3y = -2+7
5y = 5
y = 1
x - y = 1
x - 1 = 1
x = 2
b)-x+2y=12x-3y=6
-2x + 4y = 2
2x - 3y = 6
4y-3y = 2+6
y = 8
-x+2y = 1
-x + 2*8 = 1
16-1 = x
x = 15
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a)x-y=1
2x+3y=7
-2x+2y = -2
2x+3y=7
2y+3y = -2+7
5y = 5
y = 1
x - y = 1
x - 1 = 1
x = 2
b)-x+2y=1
2x-3y=6
-2x + 4y = 2
2x - 3y = 6
4y-3y = 2+6
y = 8
-x+2y = 1
-x + 2*8 = 1
16-1 = x
x = 15