Rozwiąż układ równań metodą podstawiania:
To jest układ
{4(x-2)-3(y+1)=0
{8=2(x-y)+x
4(x-2)-3(y+1)=0
8=2(x-y)+x
4x-8-3y-3=0
8=2x-2y+x
4x-3y=11
2y=3x-8
y=1,5x-4
4x-3(1,5x-4)=11
4x-4,5x+12=11
-0,5x=-1
x=2
y=3-4
y=-1
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4(x-2)-3(y+1)=0
8=2(x-y)+x
4x-8-3y-3=0
8=2x-2y+x
4x-3y=11
2y=3x-8
4x-3y=11
y=1,5x-4
4x-3(1,5x-4)=11
y=1,5x-4
4x-4,5x+12=11
y=1,5x-4
-0,5x=-1
y=1,5x-4
x=2
y=3-4
x=2
y=-1