rozwiąż układ równań metodą podstawiania
3x+2y=34
x+3y=23
Dam najj!!!!!!!!!
x=23-3y
3*(23-3y) +2y=34
69-9y+2y=34
-7y=-35
y=5
x=23-3*5
x=23-15
x=8
3(23 - 3y) +2y =34
69 - 9y +2y =34
-7y = 34 -69
-7y = - 35/: (-7)
y= 5
x= 23 - 15
x = 8
liczę na naj.. pozdrawiam
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3x+2y=34
x+3y=23
3x+2y=34
x=23-3y
3*(23-3y) +2y=34
x=23-3y
69-9y+2y=34
x=23-3y
-7y=-35
x=23-3y
y=5
x=23-3y
y=5
x=23-3*5
y=5
x=23-15
y=5
x=8
3x+2y=34
x=23-3y
3(23 - 3y) +2y =34
x=23-3y
69 - 9y +2y =34
x=23-3y
-7y = 34 -69
x=23-3y
-7y = - 35/: (-7)
x=23-3y
y= 5
x=23-3y
y=5
x= 23 - 15
y=5
x = 8
liczę na naj.. pozdrawiam