Question

rozwiąż układ równań dowolną metodą

4(x-2)-3(y+3)=3

3(x+2)-2(x-y)=5

Answer 1

4(x-2)-3(y+3)=3
3(x+2)-2(x-y)=5

 

 

4x-8-3y-9=3

3x+6-2x+2y=5

 

 

4x-3y=20

x = -1 -2y

 

 

4(-1-2y)-3y=20

x = -1 -2y  

 

 

-4-8y-3y=20

x = -1 -2y  

 

 

-11y = 24 /: (-11)

 

 x = -1 -2y 

 

y = - 24/11

x = -1 -2(-24/11)

 

 

y= -24/11

 

x = -1 + 48/11 

 

 y= - 24/11

x=  37/11

 

 

Answer 2

4(x-2)-3(y+3)=3

3(x+2)-2(x-2)=5

 

4x-8-3y-9=3

3x+6-2x+2y=5

 

4x-3y=3+9+8

x+2y=5-6 /*(-4)

 

4x-3y=20

-4x-8y=4

 

-11y=24 /:-11

y=-24/11         y=-2i2/11

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4x+3(24/11)=20

4x+72/11=20

4x=20-6i6/11

4x=13i4/11/:4

x=37/11

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