January 2019 0 12 Report
Rozwiąż układ równań:
a.
2(x+y)-3(x-y)=27
3(x+y)+(x-y)=-20


b.
(2x+y)-6(x+2y)=3
(x+2y)+2(2x+y)=6

c.
 \frac{3(y-x)}{4} -  \frac{2x-y}{2} =  \frac{1}{4}
 \frac{2x-y}{2} - \frac{y-x}{3} = \frac{1}{6}

d.
[tex] \frac{3x-y}{2} - \frac{1-y}{3} = 0
[tex] \frac{x-y}{2} + \frac{3x+y}{4} =5


+20pkt!!
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.