Rozwiąż układ równań ;)
3x-y=-6
-3x - 2y = -3
oraz
3x+2y=8
5x-2y=8
Proszę o metodę podstawiania :))
Z góry dziękuję.
-3x-2y=-3
-y=-6-3x /*(-1)
y=6+3x
-3x-2(6+3x)=-3
-3x-12-6x=-3
-9x=-3+12
-9x=9/:(-9)
x=-1
y=6+3*(-1)
y=6-3
y=3
2y=8-3x/:2
y=4-1,5x
5x-2(4-1,5x)=8
5x-8+3x=8
8x=16/:8
x=2
y=4-3
y=1
3x-y=6
-y= 6 - 3x
y=-6 + 3x
-3x- 2(6+3x)=-3
-9x=9
x=1
y=6+3*1
y=9
2y=8-3x
y=4 - 2/3
y=3 1/3
5x-2(10/3)=8
y=10/3
5x-20/3=8
5x=8+ 6 2/3
x=4 1/4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
3x-y=-6
-3x-2y=-3
-y=-6-3x /*(-1)
-3x-2y=-3
y=6+3x
-3x-2(6+3x)=-3
y=6+3x
-3x-12-6x=-3
y=6+3x
-9x=-3+12
y=6+3x
-9x=9/:(-9)
y=6+3x
x=-1
y=6+3*(-1)
x=-1
y=6-3
x=-1
y=3
x=-1
3x+2y=8
5x-2y=8
2y=8-3x/:2
5x-2y=8
y=4-1,5x
5x-2(4-1,5x)=8
y=4-1,5x
5x-8+3x=8
y=4-1,5x
8x=16/:8
y=4-1,5x
x=2
y=4-3
x=2
y=1
x=2
3x-y=6
-3x-2y=-3
-y= 6 - 3x
-3x-2y=-3
y=-6 + 3x
-3x- 2(6+3x)=-3
y=6+3x
-3x-12-6x=-3
y=6+3x
-9x=9
y=6+3x
x=1
y=6+3*1
x=1
x=1
y=9
3x+2y=8
5x-2y=8
2y=8-3x
5x-2y=8
y=4 - 2/3
5x-2y=8
y=3 1/3
5x-2(10/3)=8
y=10/3
5x-20/3=8
y=10/3
5x=8+ 6 2/3
y=10/3
x=4 1/4