Question

Rozwiąż układ równań:

(-3-x)²+(-y)²=r²
(1-x)²+(-3-y)²=r²
(1-x)²+(3-y)²=r²

Answer 1

(-3-x)²+(-y)²=r²
(1-x)²+(-3-y)²=r²
(1-x)²+(3-y)²=r²

(-3-x)²+(-y)²=(1-x)²+(-3-y)²
(1-x)²+(3-y)²=(-3-x)²+(-y)²

9+6x+x²+y²=1-2x+x²+9+6y+y²
1-2x+x²+9-6y+y²=9+6x+x²+y²

9+6x=1-2x+9+6y
1-2x+9-6y=9+6x

9+8x=10+6y
10-8x-6y=9

8x-6y=1
-8x-6y=-1
---------
-12y=0
y=0
8x=1
x=1/8
(-3-1/8)²+(0)²=r²
(-3-1/8)²=r²
r=-3 i 1/8

x=1/8
y=0
r=-3 i 1/8