Rozwiąż równianie. x²-x-56=0
x²-x-56=0
Δ=b²-4ac
Δ=1+4*56=225
√Δ=15
x1=(1-15)/2
x1=-7
x2=(1+15)/2
x2=8
^= b^2-4a*c
(delta)= 1+224=225
pierwiastek z delty=15
x1=1+15/2 = 8
x2=1-15/2= -7
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x²-x-56=0
Δ=b²-4ac
Δ=1+4*56=225
√Δ=15
x1=(1-15)/2
x1=-7
x2=(1+15)/2
x2=8
^= b^2-4a*c
(delta)= 1+224=225
pierwiastek z delty=15
x1=1+15/2 = 8
x2=1-15/2= -7