rozwiąż równanie:
x³=-x²-x
x³+x²+x=0
x(x²+x+1)=0
x²+x+1=0
Δ=1+4*1*1
Δ=5
√Δ=√5
x₁=-1-√5/2
x₂=-1+√5/2
x₃=0
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x³=-x²-x
x³+x²+x=0
x(x²+x+1)=0
x²+x+1=0
Δ=1+4*1*1
Δ=5
√Δ=√5
x₁=-1-√5/2
x₂=-1+√5/2
x₃=0