Rozwiąż równanie
(x-4)(4x-3)+3=0
4x²-3x-16x+12+3=0
4x²-19x+15=0
Δ=b²-4ac
Δ=(-19)²-4·4·15
Δ=361-240
Δ=121
√Δ=11
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(x-4)(4x-3)+3=0
4x²-3x-16x+12+3=0
4x²-19x+15=0
Δ=b²-4ac
Δ=(-19)²-4·4·15
Δ=361-240
Δ=121
√Δ=11