1/(2x-3)-((x-2)/(2x+3)=-1
zalozenie 2x-3≠0 lub 2x+3≠0
x≠3/2 lub x≠-3/2
(2x+3)-(x-2)(2x-3)-(2x-3)(2x+3)/(2x-3)(2x+3)=0
2x+3-2x²+3x+4x-6-4x²-6x+6x+9=0
-6x²+9x+6=0 I:(-3)
2x²+3x-2=0
delta=9+8=17
x1=(-3-√17)/4
x2=(-3+√17)/4
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1/(2x-3)-((x-2)/(2x+3)=-1
zalozenie 2x-3≠0 lub 2x+3≠0
x≠3/2 lub x≠-3/2
(2x+3)-(x-2)(2x-3)-(2x-3)(2x+3)/(2x-3)(2x+3)=0
2x+3-2x²+3x+4x-6-4x²-6x+6x+9=0
-6x²+9x+6=0 I:(-3)
2x²+3x-2=0
delta=9+8=17
x1=(-3-√17)/4
x2=(-3+√17)/4