Rozwiąż równanie:
3x^{2}-19x+16=0
Δ=
Δ= •3•16
Δ= 361- 192
Δ= 169 > 0
x₁=
x₂=
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3x^{2}-19x+16=0
Δ=
Δ= •3•16
Δ= 361- 192
Δ= 169 > 0
x₁=
x₁=
x₂=
x₂=