Rozwiąż równanie :
-4x² -x +3 =0
Δ=b²-4ac=(-1)² -4·( -4·3)=1+48=49
√Δ=√49=7
x₁= [-(-1)-7]/ (2· -4)= -6/-8 =¾
x₂ =[-(-1)+7]/ -8=8/ -8 =-1
to rownanie ma 2 pierwistki rowne: ¾ i -1
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-4x² -x +3 =0
Δ=b²-4ac=(-1)² -4·( -4·3)=1+48=49
√Δ=√49=7
x₁= [-(-1)-7]/ (2· -4)= -6/-8 =¾
x₂ =[-(-1)+7]/ -8=8/ -8 =-1
to rownanie ma 2 pierwistki rowne: ¾ i -1