Question

Rozwiąż równanie x^{3} -6x^{2} -2x+12=0

Answer 1

x^{3} -6x^{2} -2x+12=0

x^{2}(x-6)-2(x-6)=0

(x^{2}-2)(x-6)=0

 

(x^{2}-2)=0

x^{2}=2

x=\sqrt{2} lub x=-\sqrt{2}

 

(x-6)=0

x=6

 

Odp: x=\sqrt{2}  x=-\sqrt{2} x=6

Answer 2

x³- 6x²- 2x+ 12= 0

x²(x-6)- 2(x-6)= 0

(x²-2)(x-6)= 0

x²-2= 0 lub x-6=0

x²= 2 lub x= 6

x= √2 lub x= -√2 lub x= 6