Rozwiąż równanie x^3- 3 x^2 +4x- 12= 0
x³ - 3x² + 4x - 12 = 0
x²(x-3) + 4 (x-3) = 0
(x - 3 )(x²+4) = 0
x-3=0 ∨ x²+4=0
x=3 sprzeczne
odp:
x=3
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x³ - 3x² + 4x - 12 = 0
x²(x-3) + 4 (x-3) = 0
(x - 3 )(x²+4) = 0
x-3=0 ∨ x²+4=0
x=3 sprzeczne
odp:
x=3