Question

Rozwiąż równanie

x(2x²+3x+1)=0

Answer 1

X=0  v  2x²+3x+1=0
x=0  v  Δ=3²-4*2=9-8=1
x=1/4*(-3-1)=-1  v  x=1/4*(-3+1)= -1/2
Odp. x∈{-1, -1/2, 0}

Answer 2

x(2x²+3x+1)=0
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x = 0
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2x²+3x+1 = 0
Δ = 9-4*2*1=1
√Δ=1

x₁ = -3-1/4 = -1
x₂ = -3+1/4= -1/2

Odpowiedź : x = 0, x = -1/2, x = -1