Rozwiąż równanie (x-3)(x+2)=(x+4)(2-x)-14
(x-3)(x+2)=(x+4)(2-x)-14
x² + 2x - 3x - 6 = 2x - x² + 8 - 4x - 14
x² + 2x - 3x - 6 - 2x + x² - 8 + 4x + 14 = 0
2x² + x = 0
x(2x +1) = 0
x = 0 lub 2x + 1 = 0
2x = -1
x = -1/2
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(x-3)(x+2)=(x+4)(2-x)-14
x² + 2x - 3x - 6 = 2x - x² + 8 - 4x - 14
x² + 2x - 3x - 6 - 2x + x² - 8 + 4x + 14 = 0
2x² + x = 0
x(2x +1) = 0
x = 0 lub 2x + 1 = 0
2x = -1
x = -1/2