Rozwiąż równanie: (x-3)(x+2)=(x+4)(2-x)-14
x^2+2x-3x-6=2x-x^2+8-4x-14
x^2-x-6=-2x-x^2-6
-x-6=-2x-2x^2-6
-6=3x-2x^2-6
0=3x-2x^2
x^2-x-6+2x+x^2+6=0
2x^2-x=0
delta=b^2-4ac
delta=1^2-4*2*0=1
x= -1-1/4 = -0,5
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x^2+2x-3x-6=2x-x^2+8-4x-14
x^2-x-6=-2x-x^2-6
-x-6=-2x-2x^2-6
-6=3x-2x^2-6
0=3x-2x^2
x^2+2x-3x-6=2x-x^2+8-4x-14
x^2-x-6=-2x-x^2-6
x^2-x-6+2x+x^2+6=0
2x^2-x=0
delta=b^2-4ac
delta=1^2-4*2*0=1
x= -1-1/4 = -0,5