Question

Rozwiąż równanie:
x³-12x²+x-12=0

Answer 1

X³-12x²+x-12=0
x³+x-12x²-12=0
x(x²+1)-12(x²+1)=0
(x-12)(x²+1)=0
x=12

Answer 2

X³-12x²+x-12 =0
x²(x-12)+1(x-12)=0
(x²+1)(x-12)=0
x²+1=0 x-12=0
x²≠-1 x=12