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(x² + 4x)[(x² + 4x) + 7 + 12 ]= 0
(x² + 4x)(x² + 4x + 7 + 12) = 0
(x² + 4x)(x² + 4x + 19) = 0
x(x + 4)(x² + 4x + 19) = 0
x = 0
lub
x + 4 = 0
x = - 4
lub
x² + 4x + 19 = 0
Δ = 16 - 76 = - 60 < 0
równanie nie ma pierwiastków więc
x = 0 lub x = - 4