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sin2x = -cos2x
sin2x/cos2x = -1 założenie cos2x ≠0 !!!
tg2x = -1
2*x = 3π/4 + πk k ∈ Z
x = (3π/4 + πk)/2
x = 3π/8 + πk/2 k ∈ Z
lub mozna zapisac odpowiedz tak:
2*x = -π/4 + πk k ∈ Z
x = (-π/4 + πk)/2
x = πk/2 - π/8 k ∈ Z