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x(x+1) = 0
x=0 ∨x+1 = 0
x = -1
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b) x² - 2x =0
x( x-2) =0
x = 0 ∨ x-2 =0
x = 2
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c) 2x² + x =0
2x(x+1) = 0
2x=0 ∨ x+1 = 0
x=0 x = -1
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b) x² - 2x + 1 =0
( x-1)² = 0
(x-1)(x-1) = 0
x-1 = 0
x = 1 - pierwiastek(rozwiązanie) podwójny
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e) 9x² + 6x + 1 = 0
(3x+1)² = 0
(3x+1)(3x+1) = 0
3x+1 = 0
3x = -1 I: 3
x = - 1/3 - pierwiastek podwójny
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f) 25x² -20x + 4 = 0
(5x -2)² = 0
(5x-2)(5x-2) = 0
5x -2 = 0
5x = 2 I:5
x = 2/5 - pierwiastek podwójny
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