rozwiąż równanie. (II kl. gim :)
1) 1 - x = 1 + x
_____ _____ (ma wyjść minus jedna siudma)
4 3
2) 2 - 3x 7
_______ = ____ ( ma wyjść -4)
6 3
3) x + 4 x - 2
_______ = ______ ( ma wyjść 14)
3 2
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rozwiazanie w zalaczniku
1 - x = 1 + x
_____ _____ / *12
4 3
3-3x=4+4x
-7x= -1 / (-7)
x= - \frac{1}{7}
\frac{2-3x}{6} = \frac{7}{3} / *6
2-3x=14
-3x=12 / (-3)
x= -4
\frac{x+4}{3} = \frac{x-2}{2} / * 6
2x+8 = 3x-6
-x = -14
x=14