Odpowiedź:
f)
x - 2x² = x² - 4
- 2x² - x² + x + 4 = 0
- 3x² + x + 4 = 0
a = - 3 , b = 1 , c = 4
Δ = b² - 4ac = 1² - 4 * (- 3) * 4 = 1 + 48 = 49
√Δ = √49 = 7
x₁ = (- b - √Δ)/2a = (- 1 - 7)/(- 6) = 8/6 = 1 2/6 = 1 1/3
x₂ = (- b + √Δ)/2a = (- 1 + 7)/(- 6) = 6/(- 6) = - 1
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Odpowiedź:
f)
x - 2x² = x² - 4
- 2x² - x² + x + 4 = 0
- 3x² + x + 4 = 0
a = - 3 , b = 1 , c = 4
Δ = b² - 4ac = 1² - 4 * (- 3) * 4 = 1 + 48 = 49
√Δ = √49 = 7
x₁ = (- b - √Δ)/2a = (- 1 - 7)/(- 6) = 8/6 = 1 2/6 = 1 1/3
x₂ = (- b + √Δ)/2a = (- 1 + 7)/(- 6) = 6/(- 6) = - 1