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a^2 +6a -27 =0
delta = b^2 - 4ac
delta = 36 - 4 * 1 *(-27)
delta = 144
pierw.(delta) = 12
x1 = (-b +pierw(delta)) /2a
x2 = (-b -pierw(delta)) /2a
x1 = (-6+12)/2
x1 = 6/2
x1 = 3
x2 = (-6-12)/2
x2 = -18/2
x2 = -9
zatem para rozwiązaniem są liczby 3 albo -9
(3+6)*3=9*3=27
Prosze ;)