Rozwiąż równanie .
a) (x- 2)(x+2)+3x=(4+x)(x-4)
x2-4+3x=x2-16
x2+3x-x2=-16+4
3x=-12/3
x=-4
(x- 2)(x+2)+3x=(4+x)(x-4)
x^2+2x-2x-4+3x=4x-16+x^2-4x
x^2+3x-4x-x^2+4x=-16+4
3x=-12 /3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) (x- 2)(x+2)+3x=(4+x)(x-4)
x2-4+3x=x2-16
x2+3x-x2=-16+4
3x=-12/3
x=-4
(x- 2)(x+2)+3x=(4+x)(x-4)
x^2+2x-2x-4+3x=4x-16+x^2-4x
x^2+3x-4x-x^2+4x=-16+4
3x=-12 /3
x=-4