October 2018 1 26 Report

Rozwiąż równanie
a) x \sqrt{9}-2^{2}=x\sqrt{25}+\sqrt[3]{8}
b)\sqrt{4} (x+4^{0})=\sqrt[3]{64}-x
c)\frac{x}{\sqrt{36}} + (\sqrt{2})^{2}=\frac{x+3^{0}}{\sqrt{9}}-x
d) \frac{x+6^{0}}{3}-\frac{2(-9^{0}+x)}{{\sqrt {81}}}=\frac{3^{0}}{\sqrt{9}}-\frac{x}{3^{2}}


Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.