rozwiąż równanie 5x-x^2=6
5x-x2=6
-x2+5x-6=0
Δ=b^2-4ac=5^2-4*(-1)*(-6)=25-24=1
√Δ=1
-b+√Δ -5+1 -4
x1=----------- = --------- = ------- = 2
2a 2*(-1) -2
-b-√Δ -5-1 -6
x2=----------- = --------- = ------- = 3
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5x-x2=6
-x2+5x-6=0
Δ=b^2-4ac=5^2-4*(-1)*(-6)=25-24=1
√Δ=1
-b+√Δ -5+1 -4
x1=----------- = --------- = ------- = 2
2a 2*(-1) -2
-b-√Δ -5-1 -6
x2=----------- = --------- = ------- = 3
2a 2*(-1) -2