4x^3-12x^2-9x+27=0
4x^2(x-3)-9(x-3)=0
(x-3)(4x^2-9)=0
x=3 4x^2=9
x^2=4,5
x=
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4x^3-12x^2-9x+27=0
4x^2(x-3)-9(x-3)=0
(x-3)(4x^2-9)=0
x=3 4x^2=9
x^2=4,5
x=