rozwiąż równanie: -4x^{2}-16x+9=0 plisska odpiszcie jak najszybciej!
-4x²-16x+9=0
Δ=b²-4ac=(-16)²-4*(-4)*9=256+144=400
√Δ=20
x₁=[-b-√Δ]/2a=[16-20]/(-8)=-4/(-8)=1/2
x₂=[-b+√Δ]/2a[16+20]/(-8)=36/(-8)=-9/2
Δ=b²-4ac=256 + 144=400
x1=(-b-√Δ)/2a=(16-20)/-8=-4/-8=1/2
x2=(-b+√Δ)/2a= (16+20)/-8=36/-8=-9/2
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-4x²-16x+9=0
Δ=b²-4ac=(-16)²-4*(-4)*9=256+144=400
√Δ=20
x₁=[-b-√Δ]/2a=[16-20]/(-8)=-4/(-8)=1/2
x₂=[-b+√Δ]/2a[16+20]/(-8)=36/(-8)=-9/2
Δ=b²-4ac=256 + 144=400
√Δ=20
x1=(-b-√Δ)/2a=(16-20)/-8=-4/-8=1/2
x2=(-b+√Δ)/2a= (16+20)/-8=36/-8=-9/2