Rozwiąż równanie 4x³+12x²-x-3=0
4x³+12x²-x-3=0
4x²(x+3)-(x+3)=0
(x+3)(4x²-1)=0
x=-3
4x²=1
x²=1/4
x=1/2 lub x=-1/2 lub x=-3
(4x²-1)(x+3)=0
4x²=1/4 x₂=-3
x²=¼
x₁=½ lub x₁=-½
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4x³+12x²-x-3=0
4x²(x+3)-(x+3)=0
(x+3)(4x²-1)=0
x=-3
4x²=1
x²=1/4
x=1/2 lub x=-1/2 lub x=-3
4x²(x+3)-(x+3)=0
(4x²-1)(x+3)=0
4x²=1/4 x₂=-3
x²=¼
x₁=½ lub x₁=-½