rozwiąż równanie 2xkwadrat=3-5x
2x²=3-5x
2x²+5x-3=0
Δ=25+24=49
√Δ=7
x1=(-5+7)4=1/2
x2=(-5-7)4=-3
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2x²=3-5x
2x²+5x-3=0
Δ=25+24=49
√Δ=7
x1=(-5+7)4=1/2
x2=(-5-7)4=-3