rozwiąż równanie 2xdo kwadratu-10x+1=0
Δ=100-4*2*1
Δ=92
√Δ=√92
x1=(10+√92)/4
x2=(10-√92)/4
2x² - 10x + 1 = 0a = 2, b = -10, c = 1Δ = b² - 4acΔ = (-10)² - 4 * 2 * 1 Δ = 100 - 8Δ = 92Δ = √92x₁ = -b - √Δ / 2ax₁ = -(-10) - √92 / 2 * 2x₁ = 10 + √92 / 4x₂ = -b + √Δx₂ = 10 - √92 / 4
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Δ=100-4*2*1
Δ=92
√Δ=√92
x1=(10+√92)/4
x2=(10-√92)/4
2x² - 10x + 1 = 0
a = 2, b = -10, c = 1
Δ = b² - 4ac
Δ = (-10)² - 4 * 2 * 1
Δ = 100 - 8
Δ = 92
Δ = √92
x₁ = -b - √Δ / 2a
x₁ = -(-10) - √92 / 2 * 2
x₁ = 10 + √92 / 4
x₂ = -b + √Δ
x₂ = 10 - √92 / 4