rozwiąż równanie
2 2
a-[ x-1] - [ x+2] = 6
2 2 2
B- [ 3-x] + [2x + 1]= 5x
rozwiąż równanie
2 2
[ 2x -1 ] = [ 2x +3]
2 jest napisana do kwadratu
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a) [x - 1]² - [x+2]² = 6
x² - 2x + 1 - [x² + 4x + 4] = 6
x² - 2x + 1 - x² - 4x - 4 = 6
- 6x = 6 + 3
- 6x = 9 | :(-6)
x = - 9/6
x = - 3/2
x = - 1,5
b) [3 - x]² + [2x + 1]² = 5x²
9 - 6x + x² + 4x² + 4x + 1 = 5x²
- 2x = -1 |:(-2)
x = 1/2
c) [2x -1]² = [2x +3]²
4x² - 4x + 1 = 4x² + 12x + 9
- 16x = 8 |:(-16)
x = - 8/16
x = - 1/2