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1/log x-1 + 3/ log x+1=2 zał: x>0
podstawiamy: t= log x
1/t-1 +3/t+1 =2 /*(t-1)(t+1)
t+1+3(t-1)=2(t²-1)
t+1+3t-3=2t²-2
4t-2=2t²-2
2t²-4t=0
2t(t-2)=0
t=0 lub t=2
czyli
log x=0 lub log x=2
x=10⁰ lub x=10²
x=1 lub x=100