Question

Rozwiąż równanie

1) 4(2x-3)-6(x-3)=8
2) 5 = 3 - 2(x+8) +8 (2x-3)
3) 1- [2-5(X+1)] =8

Answer 1

1)

4(2x-3)-6(x-3)=8

8x - 12 - 6x + 18= 8

8x - 6x - 12 + 18= 8

2x + 6 = 8

2x= 8 - 6

2x= 2

x= 2 : 2

x= 1



spr.
4(2x-3)-6(x-3)=8
L= 4(2x-3)-6(x-3) = 4 (2*1 - 3) - 6(1-3) = 4(2 -3) - 6*(-2) = 4 * (-1) - (-12)= - 4+12=8
P=8
8=8
L=P



2)

5 = 3 - 2(x+8) +8 (2x-3) 

5 = 3 - 2x - 16 + 16x - 24

5= -2x + 16x  + 3 - 16 - 24

5= 14x - 37

5 + 37 = 14x

42 = 14x  /:14

42 : 14= x

3=x


spr.
5 = 3 - 2(x+8) +8 (2x-3) 
L = 5
P = 3 - 2(x+8) +8 (2x-3) = 3 - 2(3+8)+8(2*3-3)= 3 - 2*11 + 8* (6-3)= 3-22 + 8*3= -19 + 24= 5
5=5
L=P




3)

1- [2-5(x+1)] =8

1 -[ 2 - 5x - 5 ] = 8

1 - [ 5x +2 -5] = 8

1 - [5x -3] = 8

1 - 5x + 3 =8

-5x +1 + 3= 8

-5x + 4= 8

- 5x= 8 -4

5x= 4

x= 4 : 5

x= 0,8


spr.
1- [2-5(x+1)] =8
L= 1 - [2-5(x+1)] =  1 - [ 2 - 5(0,8 +1)] = 1 - [ 2 - 5*1,8] = 1 - [ 2 - 9] = 1 - [-7]=  1+7=8
8=8
L=P